Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with stepbystep explanations, just like a math tutor Factorise (i) x 3 2x 2 x 2 (ii) x 3 3x 2 9x 5 iii) x 3 13x 2 32x (iv) 2y 3 y 2 2y 1 Solution (i) Let p(x) = x 3 2x 2 x 2 By the factor theorem we know that x a is a factor of p (x) if p (a) = 0 We shall find a factor of p(x) by using some trial value of x, say x = 1 p(1) = (1) 3 2(1) 2 1 2 = 1 2Advanced Math questions and answers (2x 1)y ′′ − 2y ′ − (2x 3)y = (2x 1)2 y1 = e−x please help me to solve this nonhomogenous equation step by step using reduction of order to find general solution to it
Ex 14 2 3 Iii Factorise 2x 3 2xy 2 2xz 2 Ex 14 2
Factorise (2y x)^2(y-2x) (2x y)^2(2x-y)
Factorise (2y x)^2(y-2x) (2x y)^2(2x-y)-KCET If 2x2y = 2xy, then (dy/dx) is (A) 2yx (B) 2yx 2xy (D) (2y1/2x1) Check Answer and Solution for above Mathematics question Tardigrade 1 This answer is not useful Show activity on this post Divide the whole equation by x 2 So it will become y 2 d x 2 x y d y − d y x y d x x 2 = 0 Integrate both sidesThen you will get y 2 x − y x = c which is the correct solution where c is an integration constant Unfornutaley, your answer is incorrect
Factor x^32x^2x2 Natural Language;View Full Answer 2x 2y2x2y =4x4y 0 (xy) 2 2 x 2y = (xy) (xy) 2 (xy) ( x y ) (x y 2) Siddhant because he wrote 2 after (xy) I think he meantThe lefthand side, we're left with just a 2y, and then the righthand side becomes 6x minus 4 So 2y is equal to 6x minus 4 And then to get everything in terms to solve for y, we just have to divide everything by 2 So let's divide everything by 2, and we get y is equal to 3x minus 2
SolutionShow Solution 25 (2x y) 2 16 (x y) 2 = 5 (2x y) 2 4 (xy) 2 = (10x 5y) 2 (4x 4y) 2 = (10x 5y 4x 4y) (10x 5y 4x 4y) = (14x y) (6x 9y) = (14x y) 3 (2x 3y) = 3 (14x y) (2x 3y) Concept Factorisation by Difference of Two SquaresSimple and best practice solution for (2x^3xy^22y3)dx(x^2y2x)dy=0 equation Check how easy it is, and learn it for the future Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework If it's not what You are looking for type in the equation solver your own equation and let us solve itFactorise x^22xyy^2〖4z〗^2Factorise x2 2xy y2 4z2
Factor the expressions that are not already factored \frac {2\left (xy\right)^ {2}} {x\left (xy\right)y^ {2}} x ( − x y) y 2 − 2 ( − x y) 2 Cancel out xy in both numerator and denominator Cancel out − x y in both numerator and denominator \frac {2\left (Simplify\\frac{1}{x1}\cdot \frac{x^2}{5} simplify\\frac{x^24x45}{x^2x30} simplify\\frac{x^214x49}{49x^2} simplify\\frac{6}{x1}\frac{3}{x1} simplify\\frac{5x}{6}\frac{3x}{2}Factorise (2y x)^2(y2x) (2x y)^2(2xy) x^2xyc =intdy=int2xydx =y=(2x^2)/2xyc =y=x^2xyc Hope it helps!Click here👆to get an answer to your question ️ Simplify (x y) (2x y) (x 2y)(x y) Join / Login > 8th > Maths > Algebraic Expressions and Identities > Operations on Algebraic ExpressionsCan you please re check the question i am not
Giải hệ PT \(\left\{{}\begin{matrix}x^2y^2=2x^2y\\xy^22x^2=1\end{matrix}\right\) Theo dõi Vi phạm Toán 10 Chương 3 Bài 3 Trắc nghiệm Toán 10 Chương 3 Bài 3If a matrix A= (3x,x)(x,2x) is a solution of the equation x^2 – 5x 7 = 0, find any one value of X asked Jan 15 in Matrices by Sadhri ( 293k points) matrices Transcript Example 21 Factorize 4x2 y2 z2 – 4xy – 2yz 4xz 4x2 y2 z2 – 4xy – 2yz 4xz = 22 x2 y2 z2 – 4xy – 2yz 4xz = (2x)2 y2 z2
X2y=2, 2xy=1 panel completo » x^2 x^ {\msquare} \log_ {\msquare} \sqrt {\square} \nthroot \msquare {\square} \le \geFactorise(xy)22x2y Share with your friends Share 0 = 2x 2y 2x 2y = 2(2x) 2(2y) = 2(2x 2y ) 0 ;1st 2xy=12 To graph this line you need two points Let x=0 then y=12 giving you the point (012) Let y=0 the x=6 giving you the point (6,0) Plot these two points on a coordinate system
A) 2x 2y x 2 2xy y 2 Ta có2(xy)(x 22xyy 2) =2(xy)(xy) 2 =2(xy)(xy)(xy) =(xy)2(xy) b)x 42x 2 Ta có x 42x 2 =x 2(x 22) = x 2(x 2\(\left(\sqrt{2}\right)^2\)) =x 2(x\(\sqrt{2}\))(x \(\sqrt{2}\)) c)x 4 4 Ta có x 4 4 =(x 2) 2 2 2 2x 224x 2 =(x 2 2) 2(2x) 2 =(x 2 22x)(x 2 22x)2xxx2y*3y*y= Simple and best practice solution for 2xxx2y*3y*y= equation Check how easy it is, and learn it for the future Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework If it's not what You are looking for type in the equation solver your own equation and let us solve itA polynomial can be written as the product of its factors having a degree less than or equal to the original polynomia l The process of factoring is called factorization of polynomials Given that x3 – 2x2 – x 2 Grouping the 1 st and 3 nd terms together
Sahil Sharma, added an answer, on 2/9/13 Sahil Sharma answered this it is a good question took a lot of time i think your question is wrong if in the first term you would replace (y 2x) with (2y x) then the solution would be (2yx) 2 (2yx) (2xy) 2 (2xy) Solve $(3x^2y^4 2xy)dx (2x^3y^3 x^2)dy$ This is not one of the standard forms and neither is it an exact form How do I go about doing this question? Given, 2x y 2z = 2, x 2y z = 4, x y λz = 4, then the value of λ such that the given system of equations has no solution, is ← Prev Question Next Question → 0 votes
Factorise (x2y)^2(2xy)^2 tigerad123i tigerad123i Math Secondary School answered Factorise (x2y)^2(2xy)^2 1 See answer tigerad123i is waiting for your help Add your answer and earn points sathyamargerate0410 sathyamargerate0410 Factorise 25 (2x y)2 – 16(x – y)2Factorización por aspa doble Síguenos en Twitter y FaceBook para cualquier duda, preguntas, ejercicios puntuales Enseñamos para aprender, aprendemos para e
The line x= 0 converts to u= 2(0) 3y, v= (0) y so y= v Then u= 3(v) Another boundary is u= 3v (Which is, of course, parallel to the previous line) The line y= x converts to u= 2x 3(x)= x, v= x (x)= 0 One boundary is v= 0 (Since x can be anything, u can be anything) The line y= x1 converts to u= 2x3(x1)= 2x3x 3= x 3, vMath Input NEW Use textbook math notation to enter your math Try itY'=2x/(yx^2y), y(0)=2 a) Find the solution of the given inial value problem in explicit form b)Plot the graph of the solution c)Determine(at least appoximately) the interval inClick here👆to get an answer to your question ️ Factorise ( x 2y ) ^2 4 ( 2x y ) ^2X^2y^2 2x2y (xy)(xy)2(xy) (xy)(xy2) ans
(x 2 − 3 x) 2 − 5 (x 2 3 x) − y (x 2 3 x) 5 y = (x 2 3 x − 5) (x 2 3 x − y) 2y = 2 y = 2/2 = 1 y 2z = 1 1 2z = 1 2z = 1 1 2z = 0 z = 02xyz=32x 1 0 = 32x = 3 12x = 2 x = 2/2 = 1 Q2 The answer is x = 37, y = 84, z = 35 (i) xyz=8 (ii) 4x4y5z=7 (iii) 2x2z=4 _____ Divide the third equation by 2 and rewrite z in the term of x (iii) xz=2 z = 2 x _____ Substitute z from the third equation Step 1) Because the first equation is already solved for y, substitute (x 2) for both occurrences of y in the second equation and solve for x y = − 2x 2y becomes (x 2) = −2x 2(x 2) x 2 = − 2x 2x 4 x 2 = 0 4 x 2 = 4 x 2 − 2 = 4 − 2
Answer (1 of 3) x^2y^2 2x2y (xy)(xy)2(xy) (xy)(xy2) ansX Y x=y2 y=x2 (1,1) (4,2) Figure 2 The area between x = y2 and y = x − 2 split into two subregions If we slice the region between the two curves this way, we need to consider two different regions Where x > 1, the region's lower bound is the straight line For x < 1, however, the region's lower bound is the lower half of the f(x)(x,y)=e^(2x)2(xy^22y)e^(2x) f(y)(x,y)=(2y2)e^(2x) 分别令它们=0 解出x=05,y=1 极值点且为极小值 所以极值为f(05,1)=e/2 函数极值意义: 如果函数在闭合区间上是连续的,则通过极值定理存在整个定义域上的最大值和最小值。
Consider the curve given by y^2 = 2xy (a) show that dy/dx= y/(2yx) (b) Find all points (x,y) on the curve where the line tangent to the curve has slope 1/2 (c) Show that there are now points (x,y) on the curve where the line calculus 1 Given the curve a Find an expression for the slope of the curve at any point (x, y) on the curve2x·2y = 4xy if 0 ≤ x ≤ 1 and 0 ≤ y ≤ 1 0otherwise is exactly the same as f(x,y), the joint density, for all x and y Example 4 X and Y are independent continuous random variables, each with pdf g(w) =Find dy/dx x^2yy^2x=2 x2y y2x = −2 x 2 y y 2 x = 2 Differentiate both sides of the equation d dx (x2yy2x) = d dx (−2) d d x ( x 2 y y 2 x) = d d x ( 2) Differentiate the left side of the equation Tap for more steps By the Sum Rule, the derivative of x 2 y y 2 x x 2 y y 2 x with respect to x x is d d x x 2 y d d
Q1Solve the following and verify 2 (4x – 2) = 4(x 1) Q2 (a) A father is 35 years more than his son's age After 5 years the father's age will be twice of his son's ageFind the present age of both Q2(b) Find the value of (5⁻¹ ) ( 6⁻¹)⁻¹ 2 points= (x 2 y) 2 − (2 (2 x − y)) 2 = ( x 2 y ) 2 − ( 4 x − 2 y ) 2 is of the form a 2 − b 2 = ( a − b ) ( a b ) = ( x 2 y − 4 x 2 y ) ( x 2 y 4 x − 2 y ) The factors are (xy)(xy) or (xy)^2 We need to factor the trinomial x^22xyy^2 The factors of x^2 = (x)(x) The factors of y^2 = (y)(y) Since the second sign is positive we are adding the factors meaning the signs of the factors need to be the same Since the first sign is negative both signs must be negative
Factorise The Given Equation 2y 3 Y 2 2y 1 Factorise the given equation 2y 3 y 2 2y 1 Answer A polynomial is an algebraic expression in which the exponent on any variable is a whole number Polynomial's degree is the highest or the greatest power ofThe area bounded by y=(2x)1 /2 and x=(2y)1 /2 is (A) (4/3) sq units (B) (13/2) sq units (12/5) sq units (D) (4/25) sq units Check Answer andTaking (2x 5y) common from both terms = (2x 5y) 2 (3x 4y) 6 (x y) = (2x 5y) (6x 8y 6x 6y) = (2x 5y) (8y 6y) = (2x 5y) (14y) = (2x 5y)14y Concept Factorisation by Taking Out Common Factors Report Error
You can use the quadratic formula x^2 (2y)x (y^2) = 0\to \\ x= \frac{2y \pm \sqrt{4y^2 4(1)(y^2)}}{2} \\ =y \pm\sqrt{2}y = (1 \pm \sqrt{2})y So x^2 2xy y^2 = x (1\sqrt{2})yxExtended Keyboard Examples Upload Random Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, history, geography, engineering, mathematics, linguistics, sports, finance, music2x^2 3xy 4y^2 6x 3y 4 = 0 Natural Language;
Found 2 solutions by stanbon, funmath Answer by stanbon (757) ( Show Source ) You can put this solution on YOUR website!
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